Kako beremo vsebino nekega URL

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//  A Java program that demonstrates a procedure that can be
//  used to download the contents of a specified URL.
import java.io.*;
import java.net.*;

public class DnldURL {

   public static void main (String[ ] args) {

      URL u;
      InputStream is = null;
      DataInputStream dis;
      String s;

      try {
         u = new URL("http://200.210.220.1:8080/index.html");
         is = u.openStream();
         dis = new DataInputStream(new BufferedInputStream(is));

         while ((s = dis.readLine()) != null) {
            System.out.println(s);
         }

      } catch (MalformedURLException mue) {

         System.out.println("Ouch - a MalformedURLException happened.");
         mue.printStackTrace();
         System.exit(1);

      } catch (IOException ioe) {

         System.out.println("Oops- an IOException happened.");
         ioe.printStackTrace();
         System.exit(1);

      } finally {
         try {
            is.close();
         } catch (IOException ioe) {    }
      }
   }
}
 
 

Komentar

Namesto fiksnega URL naslova bi lahko le tega podali kot argument v ukazni vrstici. VV tem primeru bi morali v programu uporabiti stavek te oblike:
 

u = new URL(args[0]);

Program je malo zakompliciran, ker predvideva reakcije tudi v primerih, da se malo zatipkamo. Do izjeme MalformedURLException  bi na primer pri�lo, �e bi vtipkali namesto  "http" pomotoma  "htp".  Do izjeme  IOException bi na primer pri�lo, �e bi vpisali napa�no ime datoteke.
 

Kako program prevedemo in preskusimo:

Ob predpostavki, da imamo pravilno in�taliran JDK, napi�imo:

javac DnldURL.java

java DnldURL

java DnldURL > url.out